Calculate the work done (in joules) when 58.3 g of tin dissolves in excess acid at
1.07 atm
and
28
°
C.
Assume ideal gas behavior.
Sn(s) + 2H+(aq)
→ Sn2+(aq) + H2(g) |
Solution:
For the reaction:
Sn + 2H+ = Sn2+ + H2
Step1) Calculation of number of moles of Sn:
Number of moles(n) = mass / molar mass
= 58.3g/118.71 gmol-1 = 0.491 mol
Step 2) Calculation of Volume:
From ideal gas equation, PV =nRT
P = 1.07 atm, R =0.0821 L.atm /mol K, T = 28 +273 =301 K
Then, V = n RT / P
V= 0.491mol x 0.0821 L atm mol-1 K-1 x 301 K / 1.07 atm
V = 11.34 L
Step 3): Calculation of work done:
W = - PV = -1.07 atm x 11.34 L
W = -1.07 x 101325 N m-2 x 11.34 x10^-3 m3
W = -1229.46 J
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