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1. Lead(II) sulfide dissolves in excess nitric acid according to the equation below. Calculate the volume of NO(g) at 27 °C a
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Answer #1

1) 3 mole PbS give 2 mole NO

3×239.3 g PbS give 2 mole NO

4.7 g PbS give 2×4.7/3×239.3 g NO

= 0.3928 g NO

= 0.013 mole NO

Using ideal gas equation ,

Volume = nRT/P = 0.013×0.082×300.15/1.1

= 0.29 L

Answer is A)

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