Homework Answers
1) The volume of KOH is calculated:
Vb = Ca * Va / Cb = 0.198 M * 25.8 mL / 0.132 M = 38.7 mL
2) Soluble hydroxide is Mg (OH) 2.
3) The strong acid is HNO3.
4) The volume of KOH is calculated:
Vb = Ca * Va / Cb = 0.198 M * 25.8 mL / 0.132 M = 38.7 mL
5) The theoretical grams of KCl are calculated:
g theoretical KCl = 2 g KClO3 * (1 mol KClO3 / 122.6 g) * (2 mol KCl / 2 mol KClO3) * (74.6 g KCl / 1 mol) = 1.22 g KCl
The percentage is calculated:
% KCl = 1 g * 100 / 1.22 g = 82.2%
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