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29,31,32 please 29) A student prepared a stock solution by dissolving 15.0 g of KOH in...
28) How many milliliters of a 9.0 M H2504 solution are needed to make 0.45 Lof a 3.5 M solution? Vi=MzV2 - 3.5x450 175ml A) O. 18 ml B) 1.2 ml C) 180 ml D) 1200 ml 29) A student prepared a stock solution by dissolving 15.0 g of KOH in enough water to make 150. mL of solution. She then took 15.0 mL of the stock solution and diluted it with enough water to make water to make 65.0...
27) What is the concentration (molarity) of HCI in the final solution when 65 mL of a 9.0 M HCl solution is diluted with pure water to a total volume of 0.15 L? 28) How many milliliters of a 9.0 M H2SO4 solution are needed to make 0. 45 L of a 3.5 M solution? A) 0. 18 mL B) 1.2 mL C) 180 mL D) 1200 mL 29) A student prepared a stock solution by dissolving 15.0 g of...
A student prepared a stock solution by dissolving 5.00 g of KOH in enough water to make 150. mL of solution. She then took 15.0 mL of the stock solution and diluted itwith enough water to make water to make 65.0 mL of a final solution. What is the concentration of KOH for the final solution?A) 0.137 MB) 7.30 MC)5.61 MD) 0.178 M
2. A student prepared a stock solution by dissolving 15.0 g of NaOH in enough water to make 150 mL of a stock solution. She then took 22.5 mL of the stock solution and diluted it with enough water to make 250. mL of a working solution. (5 pts. each) A. What is the molar concentration of NaOH in the stock solution? # of moles x 1000 Naot mass= 15,09 g molanty volume of source (m) Mol 40 g/mol voline...
2. A student prepared a stock solution by dissolving 15.0 g of NaOH in enough water to make 150. mL of a stock solution. She then took 22.5 mL of the stock solution and diluted it with enough water to make 250. mL of a working solution. A. What is the molar concentration of NaOH in the stock solution? B. What is the molar concentration of NaOH in the working solution? C. How much of the working solution will she...
2. A student prepared a stock solution by dissolving 15.0 g of NaOH in enough water to make 150. mL of a stock solution. She then took 22.5 mL of the stock solution and diluted it with enough water to make 250. mL of a working solution. (5 pts. each) A. What is the molar concentration of NaOH in the stock solution? B. What is the molar concentration of NaOH in the working solution? C. How much of the working...
mem%20210%20FINAL%20EXAM%20(SU20)%20.pdf Imported From Sa.. 2. A student prepared a stock solution by dissolving 15.0 g of NaOH in enough water to make 150 mL of a stock solution. She then took 22.5 ml of the stock solution and diluted it with enough water to make 250 mL of a working solution. (5 pts. each) A. What is the molar concentration of NaOH in the stock solution? B. What is the molar concentration of NaOH in the working solution? C. How...
In a titration, a student found that 42.6 mL of a KOH solution were required to neurtralize 28.9 mL of a 0.160 M sulfuric acid solution. Determine the molarity of the KOH solution. SHOW WORK. 2KOH(aq) + H2SO4(aq) ------> K2SO4(aq) + 2H2O(l)
What is the molarity of a solution prepared by dissolving 15.0 g NaCl in enough water to make 1.50 L of solution?
A volume of 70.0 mL of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid (H2SO4). What was the molarity of the KOH solution if 15.2 mL of 1.50 M H2SO4 was needed? The equation is 2KOH(aq)+H2SO4(aq)?K2SO4(aq)+2H2O(l) part b: Redox titrations are used to determine the amounts of oxidizing and reducing agents in solution. For example, a solution of hydrogen peroxide, H2O2, can be titrated against a solution of potassium permanganate, KMnO4. The following equation represents...