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27) What is the concentration (molarity) of HCI in the final solution when 65 mL of a 9.0 M HCl solution is diluted with pure
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Hal solution Initially Finally Molarity (Mi) = am Molarity (M) = 2 Volume (Vi) = 65ml Volume (V₂) = 0.15L So: 15x103 me =150V = (3.5M) (4.50m) qM V = 1750) A 115 ml of am H. 504 required to make 0.452 of 3.5m solution

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