What is the hydroxide-ion concentration of a 0.250 M sodium oxalate (Na2C2O4) solution?
For oxalic acid (H2C2O4), Ka1 = 5.6×10–2 and Ka2 = 5.1×10–5.
Na2C2O4 = 2 Na+ C2O4 2-
C2O4 2- +H2O --> HC2O4- & OH-
at equilibrium
0.250molar -x --> --> --> x & x
Kb = [HC2O4-] [OH-] / [C2O4-2]
Kb = Kw / Ka2 = 1e-14 / 5.6e-5 = 1.78 e-10
1.78e-10 = [HC2O4-] [OH-] / [C2O4-2]
1.78e-10 = [x] [x] / [0.250]
x2 = 4.45e-11
x = [OH-] = 6.67 e-6 M
What is the hydroxide-ion concentration of a 0.250 M sodium oxalate (Na2C2O4) solution?
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