What is the molar concentration of carbonate ion in a 0.10 M solution of carbonic acid?
Ka1 = 4.3 × 10–7 ; Ka2 = 5.6 × 10–11
Please report the answer in units of M (do not write unit, only number)
Write numbers as 1.23E-5
--------------- H2CO3(aq) ----------> H^+ (aq) + HCO3^- (aq)
I-------------- 0.10------------------------0 ---------------0
C------------- -x ------------------------+x -------------- +x
E-------------- 0.10-x ---------------- +x ----------------+x
Ka1 = [H^+][HCO3^-]/[H2CO3]
4.3*10^-7 = x*x/(0.10-x)
4.3*10^-7(0.10-x) = x^2
x = 0.000207
[H^+] = x = 0.000207M
[HCO3^-] = x = 0.000207M
HCO3^- (aq) --------------> H^+ (aq) + CO3^2- (aq)
Ka2 = [H^+][CO3^2-]/[HCO3^-]
5.6*10^-11 = 0.000207[CO3^2-]/0.000207
[CO3^2-] = 5.6*10^-11M
= 5.6E-11 >>>>answer
What is the molar concentration of carbonate ion in a 0.10 M solution of carbonic acid?...
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