Question

A stock solution of Cu2+(aq) was prepared by placing 0.9157 g of solid Cu(NO3)2∙2.5 H2O in...

  1. A stock solution of Cu2+(aq) was prepared by placing 0.9157 g of solid Cu(NO3)2∙2.5 H2O in a 100.0-mL volumetric flask and diluting to the mark with water. A standard solution was then prepared by transferring 2.00 mL of the stock solution to a second 25.00-mL volumetric flask and diluting to the mark.
  1. What is the concentration (in M) of Cu2+(aq)in the stock solution?
  2. What is the concentration (in M) of Cu2+(aq)in the standard solution?
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Answer #1

a)

Answer

0.03937M

Explanation

Molar mass of Cu(NO3)2.2.5H2O = 232.591g/mol

moles of Cu(NO3)2.2.5H2O = 0.9157g/232.591g/mol = 0.003937mol

molarity is defined as number of moles of solute dissolved per liter of solution

concentration of Cu2+ = ( 0.003937mol/100ml)× 1000ml = 0.03937M

b)

Answer

0.003150M

Explanation

Dilution formula

C1 × V1 = C2 × V2

C1 = initial solution concentration, 0.03937M

V1 = Initial solution volume, 2.00mL

C2 = Final solution concentration, ?

V2 = Final solution volume, 25.00mL

C2 = C1×V1/V2

= 0.03937M × 2.00mL/25.00mL

= 0.003150M

  

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