Rank the following titrations in order of increasing pH at the equivalence point of the titration (1 = lowest pH and 5 = highest pH).
1 2 3 4 5 100.0 mL of 0.100 M HNO2
(Ka = 4.0 x 10-4) by 0.100 M NaOH
1 2 3 4 5 100.0 mL of 0.100 M HOCl (Ka = 3.5
x 10-8) by 0.100 M NaOH
1 2 3 4 5 100.0 mL of 0.100 M
C2H5NH2 (Kb = 5.6 x
10-4) by 0.100 M HCl
1 2 3 4 5 100.0 mL of 0.100 M NH3
(Kb = 1.8 x1 0-5) by 0.100 M HCl
1 2 3 4 5 100.0 mL of 0.100 M KOH by 0.100 M HCl
Rank the following titrations in order of increasing pH at the equivalence point of the titration...
1.) Rank the following titrations in order of increasing pH at the halfway point to equivalence (1 = lowest pH and 5 = highest pH). 100.0 mL of 0.100 M C2H5NH2 (Kb = 5.6 x 10-4) by 0.100 M HCl 200.0 mL of 0.100 M HC2H3O2 (Ka = 1.8 x 10-5) by 0.100 M NaOH 100.0 mL of 0.100 M HF (Ka = 7.2 x 10-4) by 0.100 M NaOH 100.0 mL of 0.100 M HCl by 0.100 M NaOH...
1) Rank the following titrations in order of increasing pH at the halfway point to equivalence (1 = lowest pH and 5 = highest pH). 100.0 mL of 0.100 M KOH by 0.100 M HCl 200.0 mL of 0.100 M HC2H3O2 (Ka = 1.8 x 10-5) by 0.100 M NaOH 100.0 mL of 0.100 M NH3 (Kb = 1.8 x1 0-5) by 0.100 M HCl 100.0 mL of 0.100 M HI by 0.100 M NaOH 100.0 mL of 0.100 M...
Calculate the pH at the halfway point and at the equivalence point for each of the following titrations a. 100.0 ml of 0.70M HC7H5O2 (Ka= 6.4x10^-5) titrated by 0.10 M NaOH pH at the halfway point = ______? pH at the equivalence point = _____? b. 100.0ml of 0.70M C2H5NH2 (Kb= 5.6x10^-4) titrated by 0.60M HN03 pH at the halfway point = ______? pH at the equivalence point = _____? c. 100.0 ml of 0.70M HCL titrated by 0.15m NaOH...
Assume an indicator works best when the equivalence point of a titration comes in the middle of the indicator range. For which of the following titrations would methyl red be the best indicator? The pH range of methyl red is 4.8 to 6.0. Select one: a. 0.100 M NH3 (Kb = 1.8 × 10–5) + 0.100 M HCl b. 0.100 M Sr(OH)2 + 0.100 M HI c. 0.100 M HF (Ka = 7.2 × 10–4) + 0.100 M NaOH d....
Calculate the pH at the halfway point and at the equivalence point for each of the following titrations. (Assume that the temperature is 25°C.) (a) 101.5 mL of 0.19 M HCO2H (Ka= 1.8 ✕ 10-4) titrated with 0.19 M KOH (b) 104.1 mL of 0.18 M (C2H5)3N (Kb = 4.0 ✕ 10-4) titrated with 0.36 M HClO4 (c) 100.9 mL of 0.47 M HClO4 titrated with 0.24 M NaOH
Determine the pH at the equivalence (stoichiometric) point in the titration of 33 mL of 0.22 M C2H5NH2(aq) with 0.16 M HCl(aq). The Kb of ethylamine is 6.5 x 10-4
Consider the molecular equations for the titration reactions below. Arrange the titrations in order of increasing pH at the equivalence point assuming identical concentrations. (See Table of weak acids and bases) Titration 1: HC7H5O2 + NaOH → H2O + NaC7H5O2 Titration 2: HNO3 + KOH → H2O + KNO3 Titration 3: NH3 + HCl → NH4+ + Cl— Titration 4; C5H5N + HCl → C5H5NH+ + Cl— Titration 5: HF + NaOH → H2O + NaF
What is the pH at the equivalence point in the titration of 50.0 mL of 0.100 M hydrofluoric acid, HF, (Ka = 7.2 x 10-4) with 0.100 M NaOH?
A. Match each type of titration to its pH at the equivalence point. Weak acid, strong base Strong acid, strong base Weak base, strong acid pH less than 7 pH equal to 7 pH greater than 7 B. A 56.0 mL volume of 0.25 M HBr is titrated with 0.50 M KOH. Calculate the pH after addition of 28.0 mL of KOH. C. Consider the titration of 50.0 mL of 0.20 M NH3 (Kb=1.8 x 10^-5) with 0.20 M HNO3....
Solve a, b and 2 1. Calculate the pH during the titration of 10.00 mL of 0.400 M hypochlorous acid with 0.500 M NaOH. First what is the initial pH (before any NaOH is added)? The Ka for HOCl is 3.0 x 10-8 M. Answer is 3.96 a. What is the pH after 10.60 mL of NaOH are added? b. What is the pH after 15.30 mL of NaOH are added? 2. Chloropropionic acid, ClCH2CH2COOH is a weak monoprotic acid...