Question

How much heat (in kJ) is evolved in converting 1.00 mol of steam at 130.0 C to ice at -50.0 C

How much heat (in kJ) is evolved in converting 1.00 mol of steam at 130.0 C to ice at -50.0 C? The heat capacity of steam is 2.01 J/g*C and of ice is 2.09 J/g*C.
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Answer #1
57 kj
answered by: jeian
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Answer #2
You must go through all of the steps from steam at 130 to ice at -50.
q to move steam at 130 to steam at 100.
q1 = mass x specific heat x delta T.

q to convert steam at 100 to liquid water at 100.
q2 = mass x heat of vaporization.

q to move water at 100 to water at zero.
q3 = mass x specific heat x delta T.

q to convert water at zero to ice at zero.
q4 = mass x heat of fusion.

q to move ice at zero to ice at -50.
q5 = mass x specific heat x delta T.

Then total q =
q1+q2+q3+q4+q5.
I notice your specific heats are listed in joules so your answer will come out in Joules and you must convert to kJ since the problem asks for kJ.
answered by: Alyna
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Answer #3
55.078
answered by: swm4ever
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