A diprotic acid, H2A,H2A, has acid dissociation constants of ?a1=4.15×10−4Ka1=4.15×10−4 and ?a2=3.73×10−12.Ka2=3.73×10−1...
A diprotic acid, H2A,H2A, has acid dissociation constants of ?a1=4.15×10−4Ka1=4.15×10−4 and ?a2=3.73×10−12.Ka2=3.73×10−12. Calculate the pH and molar concentrations of H2A,H2A, HA−,HA−, and A2−A2− at equilibrium for each of the solutions.
A 0.176 M0.176 M solution of H2A.H2A.
pH =
[H2A]=[H2A]=
MM
[HA−]=[HA−]=
MM
[A2−]=[A2−]=
MM
A 0.176 M0.176 M solution of NaHA.NaHA.
pH=
[H2A]=[H2A]=
MM
[HA−]=[HA−]=
MM
[A2−]=[A2−]=
MM
A 0.176 M0.176 M solution of Na2A.Na2A.
pH=
[H2A]=[H2A]=
MM
[HA−]=[HA−]=
MM
[A2−]=[A2−]=
M
Homework Answers
![- 1) 0.176m of HA H2A = H+HAⓇ 0.176 o o initial -x tx ax change (0.176-x) x equilibrium ka = [H* ][HA] [444] 4.15x15 =0.0083](http://img.homeworklib.com/questions/89ee51a0-18d1-11ea-b69b-efa5dd5596e5.png?x-oss-process=image/resize,w_560)
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A diprotic acid, H2A,H2A, has acid dissociation constants of ?a1=4.15×10−4Ka1=4.15×10−4 and ?a2=3.73×10−12.Ka2=3.73×10−1...
A diprotic acid, H2A, has acid dissociation constants of Ka1=1.01×10−4 and Ka2=4.08×10−12. Calculate the pH and...
A diprotic acid, H2A, has acid dissociation constants of
Ka1=1.01×10−4 and Ka2=4.08×10−12. Calculate the pH and molar
concentrations of H2A, HA−, and A2−at equilibrium for each of the
solutions.
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A diprotic acid, H2A, has acid dissociation constants of
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concentrations of H2A, HA−, and A2−at equilibrium for each of the
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A diprotic acid, H, A, has acid dissociation constants of Kal = 1.01 x 104 and K22 = 4.08 x 10-12. Calculate the pH and molar concentrations of H, A, HA, and A? at equilibrium for each of the solutions. A 0.176 M solution of H, A. pH= pH = 1...
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