Question

Draw the structure of the product formed when HBr reacts with 2-methyl-2-butene in the presence of organic peroxides....

Draw the structure of the product formed when HBr reacts with 2-methyl-2-butene in the presence of organic peroxides. When drawing hydrogen atoms on a carbon atom, either include all hydrogen atoms or none on that carbon atom, or your structure may be marked incorrect.

1 0
Add a comment Improve this question Transcribed image text
✔ Recommended Answer
Answer #1
Concepts and reason

The problem is based on the concept of reaction between alkene and hydrogen halide in the presence of peroxide. This involves free radical mechanism and substitution of halide takes place according to anti-Markonikov’s rule.

Stability of radical cation is same as that of carbocation therefore,

3° radical > 2* radical > 1° radical

Fundamentals

According to anti-Markonikov’s rule, on reaction of unsaturated alkene and hydrogen halide, addition of hydrogen takes place on carbon with more number of hydrogen atoms.

In the free radical mechanism, initiation step is as follows:


- For —— RỘ
rö tu <br>> Ro—H +•Br

Propagation step is as follows:

|
Br
.

Reaction of tertiary free radical with HBr is as follows:

+ H
I Br:
--
+ Br:

Termination step is as follows:

:Br. +
Br: —
>Br

Ans:

The major product of the reaction is as follows:

Br

Add a comment
Know the answer?
Add Answer to:
Draw the structure of the product formed when HBr reacts with 2-methyl-2-butene in the presence of organic peroxides....
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT