Predict the reaction product of treating the given alkene with the reagent shown below. Only draw one enantiomer if more than one is possible. Include H's on chirality centers.
The concept to solve this problem is bromination of alkene.
Alkene reacts with bromine molecule and forms a bridged bromonium ion followed by the attack of bromide ion (nucleophile) gives dibromo product.
The curved arrow shows the movement of the electron pair. Curved arrow is represented as:
The tail of the arrow begins at an electron pair and the head represents that moving of an electron pair.
The formation of intermediate is as follows:
Here, the intermediate is bridged bromonium ion.
The formation of required compound is as follows:
Here, the dibromocyclohexane is formed in the product.
Ans:The product of this reaction is as follows:
Predict the reaction product of treating the given alkene with the reagent shown below. Only draw...
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