For the equilibrium
Br2(g)+Cl2(g)⇌2BrCl(g)
at 400 K, Kc = 7.0.
Part A
If 0.25 mol of Br2 and 0.55 mol of Cl2 are introduced into a 3.0-L container at 400 K, what will be the equilibrium concentration of Br2?
Express your answer to two significant figures and include the appropriate units.
Part B
If 0.25 mol of Br2 and 0.55 mol of Cl2 are introduced into a 3.0-L container at 400 K, what will be the equilibrium concentration of Cl2?
Part C
If 0.25 mol of Br2 and 0.55 mol of Cl2 are introduced into a 3.0-L container at 400 K, what will be the equilibrium concentration of BrCl?
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For the equilibrium Br2(g)+Cl2(g)⇌2BrCl(g) at 400 K, Kc = 7.0. Part A If 0.25 mol of...
For the equilibrium Br2(g)+Cl2(g)⇌2BrCl(g) at 400 K, Kc = 7.0. Part A If 0.25 mol of Br2 and 0.55 mol of Cl2 are introduced into a 3.0-L container at 400 K, what will be the equilibrium concentration of Br2? Express your answer to two significant figures and include the appropriate units. Part B If 0.25 mol of Br2 and 0.55 mol of Cl2 are introduced into a 3.0-L container at 400 K, what will be the equilibrium concentration of Cl2?...
If 0.25 mol of Br2 and 0.55mol of Cl2 are introduced into a 3.0-L container at 400 K, what will be the equilibrium concentration of BrCl ?? Br2(g)+Cl2(g) 2BrCl at 400 K, Kc= 7.0
Consider this equilibrium reaction at 400 K. Br2(g)+Cl2(g)↽−−⇀2BrCl(g)?c=7.0 If the composition of the reaction mixture at 400 K is [BrCl]=0.00675, [Br2]=0.00249, and [Cl2]=0.000458, what is the reaction quotient, ?Q? ?= How is the reaction quotient related to the equilibrium constant, Kc, for this reaction?
At 400 K, the equilibrium constant for the reaction Br2 (g) + Cl2 (g) <=> 2BrCl (g) is Kp = 7.0. A closed vessel at 400 K is charged with 1.00 atm of Br2 (g), 1.00 atm of Cl2 (g), and 2.00 atm of BrCl (g). What is the equilibrium pressure of Br2? A. 0.86 atm B. The equilibrium partial pressures of Br2 will be the same as the initial value. C. The equilibrium partial pressure of Br2 will be...
For the reaction given below, the value of the equilibrium constant at 400K is 7.0 Br2(g) + Cl2(g) ßà 2BrCl(g) At equilibrium the concentration of Br2 and Cl2 are each 1 mol/L. What is the equilibrium concentration of BrCl? a. 49 mol/L b. 1.0 mol/L c. 7.0 mol/L d. 2.6 mol/L
23) At 400 K, the equilibrium constant for the reaction Br2(g) + Cl2 (9) 2BrCl (9) is Kp = 70. A closed vessel at 400 K is charged with 1.00 atm of Br2 (g) 1.00 atm of Cl2 (g), and 2.00 alm of BrCl (g). Use Q to determine which of the statements below is true. A) At equilibrium, the total pressure in the vessel will be less than the initial total pressure. B) The equilibrium partial pressures of Br2....
Consider this equilibrium reaction at 400 K. Br2(g) + Cl2(g) = 2 BrCl(g) K. = 7.0 If the composition of the reaction mixture at 400 K is [BrCl] = 0.005275 M, [Br] = 0.001971 M, and [CL] = 0.0003620 M, what is the reaction quotient, Q?
At 400K, the equilibrium constant for the reaction Br2(g) + Cl2(g) ⇌ 2BrCl(g) is KP = 7.0. A closed vessel at 400K is charged with 1.00 atm of Br2(g), 1.00 atm of Cl2(g), and 2.00 atm of BrCl(g). Use Q to determine which of the statements below is true. A. The equilibrium partial pressure of BrCl(g) will be less than 2.00 atm B. The reaction will go to completion since there are equal amounts of Br2 and Cl2 C. At...
At 400 K, the equilibrium constant for the reaction Br 2 (g) + Cl 2 (g) 2BrCl (g) is K p = 7.0. A closed vessel at 400 K is charged with 1.00 atm of Br 2 (g), 1.00 atm of Cl 2 (g), and 2.00 atm of BrCl (g). Use Q to determine which of the statements below is true. The equilibrium partial pressures of Br2, Cl2, and BrCl will be the same as the initial values. The reaction will...
1-The equilibrium constant Kc for the equation 2H2(g) + CO(g) ⇌ CH3OH(g) is 11 at a certain temperature. If there are 2.63 × 10−2 moles of H2 and 7.15 × 10−3 moles of CH3OH at equilibrium in a 6.29−L flask, what is the concentration of CO? ?M 2-In an analysis of the following reaction at 100°C,Br2(g) + Cl2(g) ⇌ 2BrCl(g) the equilibrium concentrations of the reactants were found to be [Br2] = 4.0×10−3M and [Cl2] = 7.7 ×10−3M. The equilibrium...