What is the threshold frequency ν0 of cesium? Note that 1 eV (electron volt)=1.60×10−19 J. Express your answer numerically in hertz.
Calculate the threshold frequency by using the following equation.
For threshold energy, kinetic energy will be zero.
Here, h is plank constant, is threshold frequency, and E is ionization energy.
Calculate the threshold frequency by using the values of plank constant and the energy.
Minimum amount of frequency that causes photo electric emission is called as threshold frequency.
Emission of electrons when light is incident on surface of a material is called as photo emission and this effect is called as photo electric effect.
Ionization energy of cesium is .
Substitute the values in the formula.
One cycle per second is equal to hertz. So, the threshold frequency of cesium is .
Ans:Threshold frequency of cesium atom is .
What is the threshold frequency ν0 of cesium? Note that 1 eV (electron volt)=1.60×10−19 J. Express...
For metallic cesium (Cs), the threshold energy is 1.95 eV (1 eV = 1.602·10−19 J). Find the threshold frequency and wavelength. In what part of the spectrum will Cs begin to emit photoelectrons? Describe the situation when the wavelength of the incident light is 530 nm. If applicable, find the kinetic energy and, if you are so inclined, the velocity of photoelectrons if Cs is irradiated with that light.
The Photoelectric Effect A Review Constants Periodic Table Electrons are emitted from the surface of a metal when it's exposed to light. This is called the photoelectric effect. Each metal has a certain threshold frequency of light, below which nothing happens. Right at this threshold frequency, an electron is emitted. Above this frequency, the electron is emitted and the extra energy is transferred to the electron The equation for this phenomenon is Here are some data collected on a sample...
Electrons are emitted from the surface of a metal when it's exposed to light. This is called the photoelectric effect. Each metal has a certain threshold frequency oflight, below which nothing happens. Right at this threshold frequency, an electron is emitted. Above this frequency, the electron is emitted and the extra energy istransferred to the electron.The equation for this phenomenon is KE=hv-hv0 where KE is the kinetic energy of the emitted electron, h=6.63x10^-34 J.s is Planck's constant, v is the...
The work function, Φ0 (or W0), for cesium is 3.43×10−19 J. The frequency of a photon hitting the cesium sample is 6.17×1014 Hz. (a) What is the maximum kinetic energy of an electron ejected from the sample due to the photon? (b) What is voltage required to bring the electron in part (a) to rest.
The electron volt (eV) is a convenient unit of energy for expressing atomic-scale energies. It is the amount of energy that an electron gains when subjected to a potential of 1 volt;1 eV = 1.602 ✕ 10−19 J. Using the Bohr model, determine the energy, in electron volts, of the photon produced when an electron in a hydrogen atom moves from the orbit with n = 4 to the orbit with n = 2. (Assume that the Bohr constant and...
What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays of frequency 1.60×1015Hz ?Express your answer in joules to three significant figures.
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Determine the threshold frequency for metal X (w = 3.7 X 10-19 J).