Question

The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a String rather than an Integer. At FIXME in the code, add a try/catch statement to catch java.util.InputMismatchException, and output 0 for the age.

Ex: If the input is:

Lee 18
Lua 21
Mary Beth 19
Stu 33
-1

then the output is:

Lee 19
Lua 22
Mary 0
Stu 34

Answer 1

import java.util.Scanner;
import java.util.InputMismatchException;

public class NameAgeChecker {
   
   public static void main(String[] args) {
      
      Scanner scnr = new Scanner(System.in);
      
      String inputName;
      int age;
      
      inputName = scnr.next();
      
      while (!inputName.equals("-1")) {
         
         try {
            
            age = scnr.nextInt();
            
         }
         catch (InputMismatchException ex) {
            
            age = -1;
            scnr.nextLine();
            
         }
         
         System.out.println(inputName + " " + (age + 1));
         inputName = scnr.next();
         
      }
      
   }
   
}

Answer 2

# Split input into 2 parts: name and age

parts = input().split()

name = parts[0]

while name != '-1':

    # FIXME: The following line will throw ValueError exception.

    #        Insert try/except blocks to catch the exception.

     try:

        age = get_age()

        heart_rate = fat_burning_heart_rate(age)

        print('Fat burning heart rate for a {:d} year-old: {:.1f} bpm'.format(age, heart_rate))

        

    except age = 0

        age = int(parts[1]) + 1

        print('{} {}'.format(name, age))

    

    # Get next line

    parts = input().split()

    name = parts[0]