Question

 4.18 LAB: Checker for integer string

 Forms often allow a user to enter an integer. Write a program that takes in a string representing an integer as input, and outputs yes if every

 character is a digit 0-9.

 Exx If the input is:

 1995

 the output is:

 yes

 Ex If the input is:

 42,000

 1995!

 the output is

 no

 Hint: Use a loop and the Character isDigitO function.

 418.1: LAB: Checker for integer string

Answer 1

ANSWER:-

CODE:-

import java.util.*;
public class LabProgram{
   public static void main(String[] args) {
       Scanner scnr = new Scanner(System.in);
       String userString;
       userString = scnr.nextLine();
       int len = userString.length();
       boolean isNumber = true;
       for (int i=0;i            char ch = userString.charAt(i);
           if(!Character.isDigit(ch)){
               isNumber = false;
               System.out.println("no");
           }
       }
       if(isNumber)
           System.out.println("yes");
   }
}

NOTE:- If you need any modifications in the code,please comment below.Please give positive rating.THUMBS UP.

         THANK YOU!!!!

OUTPUT:-