5.14 LAB: Convert to binary
Write a program that takes in a positive integer as input, and outputs a string of 1's and 0's representing the integer in binary. For an integer x, the algorithm is:
As long as x is greater than 0 Output x modulo 2 (remainder is either 0 or 1) Assign x with x divided by 2
Note: The above algorithm outputs the 0's and 1's in reverse order.
Ex: If the input is:
6
the output is:
011
6 in binary is 110; the algorithm outputs the bits in reverse
In Python, please. Thank you
if __name__ == '__main__': user_num = int(input()) while user_num > 0: print(user_num % 2, end='') user_num //= 2 print()
ANSWER :
This is a very straight forward question, the algo is given, and we have to just put a corresponding code to fetch the result.
CODE:
"""algorithms: As long as x is greater than 0 Output x modulo 2 (remainder is either 0 or 1) Assign x with x divided by 2""" # taking user input x = int(input()) str1 = '' # using while loop to iteratively divide by 2 while x > 0: out = x % 2 # the remainder 0 or 1 str1 += str(out) # storing the remainder in str1 x = x//2 print("output from algorithm : ",str1)
OUTPUT :
THANK YOU...!!!!
import java.util.Scanner; public class LabProgram { public static void main(String[] args) { /* Type your code here. */ Scanner scnr = new Scanner(System.in); int x; x = scnr.nextInt(); String str1 = ""; while(x>0){ int out = x % 2; String s = String.valueOf(out); str1 = str1 + s; x = x / 2; } System.out.println(str1); } }
Here is an answer to 4.14 Lab: Convert to binary in Java
sum_num = int(input()) while (sum_num > 0) : print(sum_num % 2, end='') sum_num //= 2 print()
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