Question

IN PYTHON

Write a program that reads a list of integers in the range (0 – 49) and prints out the numbers that does not repeat twice.

The first input of the program is the number of integers contained in this list, followed by the integers contained in the list. Print the numbers in in ascending order.

Case 1:

INPUT: 5 2 2 3 3 1

OUTPUT:1

Case 2:

INPUT:6 1 2 1 2 2 2

OUTPUT:2

Case 3:

INPUT:4 3 2 1 2

OUTPUT: 1 3

3

4

3 2 1 2

1

3

Answer 1

Answer:

Explanation:

First number of elements are taken as input.

Then using a loop, all the numbers are appended to a list.

Then using another loop on the sorted list, if the count of element is 1, only then it is printed out.

feel free to comment if you need any help!

Code:

n = int(input())

l=[]

for i in range(n):
num = int(input())
l.append(num)
  
for element in sorted(l):
if(l.count(element)==1):
print(element,end= ' ')

Output:

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