Question

In C++: Write a program that reads a list of integers, and outputs the two smallest integers in the list, in ascending order. The list is preceded by an integer indicating how many numbers are in the list. If the input is: 5 10 5 3 21 2, the output is: 2 3 To achieve the above, first read the integers into a vector.

Answer 1

Answer:

Explanation:

Here is the code which takes the listof integers and then uses 2 variables smallest and second_smallest to store the smallest and second smallest element of the array and then print them afterwards.

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Code:

#include <bits/stdc++.h>

using namespace std;

int main()
{
vector<int> v;
  
int n;
cin>>n;
  
for (int i = 0; i < n; i++) {
  
int num;
cin>>num;
v.push_back(num);
}
  
  
int smallest = INT_MAX, second_smallest = INT_MAX;
  
for (int i = 0; i < n; i++) {
  
if(v[i]<smallest)
{
second_smallest = smallest;
smallest = v[i];
}
else if(v[i]<second_smallest)
{
second_smallest = v[i];
}
}
  
cout<<smallest<<" "<<second_smallest<<endl;

return 0;
}

Output:

5 10 5 3 21 2 2 3 ...Program finished with exit code o Press ENTER to exit console.

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