Question

Java Programming

Write a method named isEven that accepts an integer argument. The method should return true if the argument is even, or false if not. The program’s main method should use a loop to generate a random integer. The number of random integers is provided by a user, who must enter a number greater than 10. The loop should then invoke the isEven method to determine whether each integer is even or odd, display the random number and the result. After the loop has completed, the total number of even and odd integers should be displayed.

Answer 1

import java.util.Random;
import java.util.Scanner;

public class RandomEvenCheck {
  public static boolean isEven(int n){
    return n%2 == 0;
  }
  
  public static void main(String args[]){
    Scanner scanner = new Scanner(System.in);
    System.out.print("How many random numbers? ");
    int n = scanner.nextInt();
    
    int evenCount = 0, oddCount = 0;
    Random random = new Random();
    
    int var;
    for(int i = 0;i<n;i++){
      var = random.nextInt(n);
      if(isEven(var)) {
        System.out.println(var + "is even");
        evenCount++;
      }
      else{
        System.out.println(var + "is odd");
        oddCount++;
      }
    }
    System.out.println("Number of even numbers generated: "+evenCount);
    System.out.println("Number of odd numbers generated: "+oddCount);
  }
}

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