Question

-9, -2, 0, 5, 8, 8, 17, 20, 23, 29, 69, 91. Momie Ex = 1259 21.5833 = 21.6 (estimation: one more decimal place than original data is.) 8+17 b. Median: 2 (middle number within the data set, it divides data set into two equal parts.) Mode: M = 8 (data value that most frequently repeats within the data set.) d. Range: R=H-L=91 - (-9) = 100 MR9+91 -= 41.0 e. Midrange: 2 (middle point within the range.) 2x-(*)_15339 - (259) = 886.2652 = 886.3 f. Variance: (1-1) 12.11 (estimation: one more decimal place than original data is.) 8. sVs = 886.2652 = 29.7702 29.9 (estimation: one more decimal place than original data is.) 100% -7.702.100% = 137.9% or 138% h. Coefficient of a Variance: 21.5833 1. Chebisher's Theorem: Find the proportion of data values that fall in 2 standard deviation from the mean. CVS j. k 224 or 75%, ik is a number of standard deviations, k>1) Find the interval that contains at least 75% of values. The interval is * -ks, x + ks = [21.5833 - 2 x 29.7702,21.5833+2 x 29.7702] = [-38.0.81.2] Note: All usual values are in 2 standard deviions from the mean. So, the usual values interval is: * -ks,x+ ks - [21.5833-2x 29.7702,21.5833+2 x 29.7702] = [-38.0,81.2] Find the standard deviation and the variance using range rule of thumb. 100 5 = 25° = 625 The usual values Range: R = 45 => 4 and the variance, 1. S= = 25 values Range Reds m. Z-Score: is the number of standard deviations that a value is above or below the mean s Find the 2-score of 69, which is how many standard deviations 69 is away from the mean.

can some one expalain how they  got the numbers In j and k thank you

Answer 1

j)

from part i) , using chebishev's theorem , 75% of data lies within 2 std dev away from men

so, k = 2

now, required interval is given by (sample mean ± 2 * std dev) = (21.5833 ± 2*29.7702) = (-38.0 , 81.2)

k)

usual value of range is within 2 std dev away from mean .So,

usual values interval is given by -

(sample mean ± 2 * std dev) = (21.5833 ± 2*29.7702) = (-38.0 , 81.2)

please revert for doubt..