A 0.035 mol sample of a weak acid, HA, is dissolved in 437 mL of water...
A 0.035 mol sample of a weak acid, HA, is dissolved in 437 mL of water and titrated with 0.46 M NaOH. After 28 mL of the NaOH solution has been added, the overall pH = 4.1938. Calculate the Ka value for HA. Enter your answer in the format: 1.23e-4
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A 0.035 mol sample of a weak acid, HA, is dissolved in 437 mL of
water...
3. 0.7253 g sample containing an unknown weak acid HA was dissolved in 50 mL water...
3. 0.7253 g sample containing an unknown weak acid HA was dissolved in 50 mL water and titrated against 0.1555 M NaOH, requiring 48.11 mL to of NaOH to reach the end-point. During the titration reaction, the pH of the solution is 3.77 when half of the HA is neutralized and the equivalence-point pH is 8.33. (a) State two ways to standardize the NaOH used in the titration. (b) Suggest and explain an indicator that can be used in the...
36.53 mL of a 0.223 M solution of weak acid HA are titrated with 0.2 M...
36.53 mL of a 0.223 M solution of weak acid HA are titrated with 0.2 M NaOH. What is the pH of the solution after 8.25 mL of the NaOH have been added? The Ka for the weak acid is 0.0000077101.
33.79 mL of a 0.157 M solution of weak acid HA are titrated with 0.22 M...
33.79 mL of a 0.157 M solution of weak acid HA are titrated with 0.22 M NaOH. What is the pH of the solution after 12.98 mL of the NaOH have been added? The Ka for the weak acid is 0.0000005732.
A 0.625-gram sample of an unknown weak acid (call it HA for short) is dissolved in...
A 0.625-gram sample of an unknown weak acid (call it HA for short) is dissolved in enough water to make 25.0 mL of solution. This weak acid solution is then titrated with 0.100 M NaOH and 45.0 mL of the NaOH solution is required to reach the equivalence point. Using a pH meter, the pH of the solution at the equivalence point is found to be 8.25. Determine the pKa value of the unknown acid.
2. A 0.500-gram sample of a weak, nonvolatile monoprotic acid, HA, was dissolved in sufficient water...
2. A 0.500-gram sample of a weak, nonvolatile monoprotic acid, HA, was dissolved in sufficient water to make 50.0 milliliters of solution. The solution was then titrated with a standard NaOH solution. Predict how the calculated molar mass of HA would be affected (too high, too low, or not affected) by the following laboratory procedures. Explain each of your answers. A. (2 points.). After rinsing the buret with distilled water, the buret is filled with the standard NaOH solution; the...
38.49 mL of a 0.214 M solution of weak acid HA are titrated with 0.227 M...
38.49 mL of a 0.214 M solution of weak acid HA are titrated with 0.227 M NaOH. What is the pH of the solution after 7.11 mL of the NaOH have been added? The Ka for the weak acid is 0.0000061193. I came up with 4.60. Just want to verify. Thank you.
50.0 mL sample of the weak acid the concentration of the weak acid = 0.15 M...
50.0 mL sample of the weak acid
the concentration of the weak acid = 0.15 M
25 mL of the week acid into 100 mL beaker
titrated this solution of 0.21 M NaOH
moles of weak acid = 3.75*10^-3
moles of NaOH = moles of week acid
c) How many milliliters of the NaOH are required to neutralize the sample of weak acid? d) How many moles of NaOH have been added at one half of the volume in part...
25. A 50.0 mL sample of 0.150 M weak acid was titrated with a 0,150 M...
25. A 50.0 mL sample of 0.150 M weak acid was titrated with a 0,150 M NaOH solution. What is the pH after 30.0 mL of the sodium hydroxide solution is added? The Ka of the acid is 1.9x10(3 points) D) 4.78 E) None of these C) 3.03 (A) 4.90 B) 1.34 26. A 25.0 mL sample of 0.25 M hydrofluoric acid (HF) is titrated with a 0.25 M NaOH solution. What is the pH after 38.0 mL of base...
A solid weak acid is weighed, dissolved in water and diluted to exactly 50.00 ml. 25.00 ml of the...
A solid weak acid is weighed, dissolved in water and diluted to exactly 50.00 ml. 25.00 ml of the solution is taken out and is titrated to a neutral endpoint with 0.10 M NaOH. The titrated portion is then mixed with the remaining untitrated portion and the pH of the mixture is measured. Mass of acid weighed out (grams) 0.773 Volume of NaOH required to reach endpoint: (ml) 19.0 pH of the mixture Ihalf neutralized solution 3.54 Calculate the following...
A 1.53 gram sample of an unknown monoprotic acid is dissolved in 25.0 mL of water...
A 1.53 gram sample of an unknown monoprotic acid is dissolved in 25.0 mL of water and titrated with a a 0.234 M aqueous barium hydroxide solution. It is observed that after 16.3 milliliters of barium hydroxide have been added, the pH is 4.924 and that an additional 10.0 mL of the barium hydroxide solution is required to reach the equivalence point. (1) What is the molecular weight of the acid? g/mol (2) What is the value of Ka for the...
2. A 0.500-gram sample of a weak, nonvolatile monoprotic acid, HA, was dissolved in sufficient water to make 50.0 milliliters of solution. The solution was then titrated with a standard NaOH solution. Predict how the calculated molar mass of HA would be affected (too high, too low, or not affected) by the following laboratory procedures. Explain each of your answers. A. (2 points.). After rinsing the buret with distilled water, the buret is filled with the standard NaOH solution; the...
50.0 mL sample of the weak acid
the concentration of the weak acid = 0.15 M
25 mL of the week acid into 100 mL beaker
titrated this solution of 0.21 M NaOH
moles of weak acid = 3.75*10^-3
moles of NaOH = moles of week acid
c) How many milliliters of the NaOH are required to neutralize the sample of weak acid? d) How many moles of NaOH have been added at one half of the volume in part...
25. A 50.0 mL sample of 0.150 M weak acid was titrated with a 0,150 M NaOH solution. What is the pH after 30.0 mL of the sodium hydroxide solution is added? The Ka of the acid is 1.9x10(3 points) D) 4.78 E) None of these C) 3.03 (A) 4.90 B) 1.34 26. A 25.0 mL sample of 0.25 M hydrofluoric acid (HF) is titrated with a 0.25 M NaOH solution. What is the pH after 38.0 mL of base...
A solid weak acid is weighed, dissolved in water and diluted to exactly 50.00 ml. 25.00 ml of the solution is taken out and is titrated to a neutral endpoint with 0.10 M NaOH. The titrated portion is then mixed with the remaining untitrated portion and the pH of the mixture is measured. Mass of acid weighed out (grams) 0.773 Volume of NaOH required to reach endpoint: (ml) 19.0 pH of the mixture Ihalf neutralized solution 3.54 Calculate the following...
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