You are to write a program that implements a Reverse Polish Notation Calculator in C using BISON and FLEX, You only have to edit the BISON and FLEX files.
Link to the files to start and have a general view of the program:
https://www.dropbox.com/sh/83yzs66jhftqj5b/AABZcY9Qwl84JdUFnYpQaZk9a?dl=0
Reverse Polish Notation is a mathematical notation in which every operator follows all of its operands. It is sometimes called postfix notation, and does not require any parentheses as long as each operator has a fixed number of operands.For example, this mathematical notation adds the numbers 5 and 6 together:
5 6 +
From Wikipedia:
In reverse Polish notation the operators follow their operands; for instance, to add 3 and 4, one would write "3 4 +" rather than "3 + 4". If there are multiple operations, the operator is given immediately after its second operand; so the expression written "3 − 4 + 5" in conventional notation would be written "3 4 − 5 +" in RPN: 4 is first subtracted from 3, then 5 added to it.
the algorithm to implement this type of calculator is as follows:
while there are input tokens left: read the next token if the token is a value: push it onto the stack else ( assume the token is an operator ): it is already known that the operator takes N arguments if there are fewer than N values on the stack: ERROR: The user has not provided enough input values else: pop the top N values from the stack evaluate the operator, with the values as arguments push returned results (if any) back onto the stack end if end if end while if there is only one value on the stack: that value is the result of the mathematical expression else if there are more than one value on the stack: The user input too many values endif
You are to implement a RPN calculator that supports the following operands:
+ (addition)
- (subtraction)
* (multiplication)
/ (division)
Your Task
Finish implementing the missing operators in the bison (calc.y) and flex (calc.l) files. The tasks are denoted by the TO-DO comments. The code can then be tested by the main function also provided. So only the calc.y and calc.l have to be edited.
Thank you!
#include <stdio.h>
#include <stdlib.h> / for atof() /
#define MAXOP 100 / max size of operand or operator /
#define NUMBER '0' / signal that a number was found /
int getop(char []);
void push(double);
double pop(void);
/ reverse Polish calculator /
main()
{
int type;
double op2;
char s[MAXOP];
while ((type = getop(s)) != EOF) {
switch (type) {
case NUMBER:
push(atof(s));
break;
case '+':
push(pop() + pop());
break;
case '*':
push(pop() * pop());
break;
case '-':
op2 = pop();
push(pop() - op2);
break;
case '/':
op2 = pop();
if (op2 != 0.0)
push(pop() / op2);
else
printf("error: zero divisor\n");
break;
case '\n':
printf("\t%.8g\n", pop());
break;
default:
printf("error: unknown command %s\n", s);
break;
}
}
}
#define MAXVAL 100
int sp = 0;
double val[MAXVAL];
void push(double f)
{
if(sp < MAXVAL)
val[sp++]=f;
else
printf("error:stack full, cant push %g\n",f);
}
double pop(void)
{
if(sp>0)
return val[--sp];
else
{
printf("error: stack empty\n");
return 0.0;
}
}
#include<ctype.h>
int getch(void);
void ungetch(int);
int getop(char s[])
{
int i,c;
while((s[0] = c = getch()) == ' ' || c =='\t')
;
s[1] = '\0';
i = 0;
if(!isdigit(c) && c!='.' && c!='-')
return c;
if(c=='-')
if(isdigit(c=getch()) || c == '.')
s[++i]=c;
else
{
if(c!=EOF)
ungetch(c);
return '-';
}
if(isdigit(c))
while(isdigit(s[++i] =c =getch()))
;
if(c=='.')
while(isdigit(s[++i] = c=getch()))
;
s[i] = '\0';
if(c!=EOF)
ungetch(c);
return NUMBER;
}
#define BUFSIZE 100
char buf[BUFSIZE];
int bufp = 0;
int getch(void)
{
return (bufp > 0) ? buf[--bufp] : getchar();
}
void ungetch(int c)
{
if(bufp >= BUFSIZE)
printf("ungetch: too many characters\n");
else
buf[bufp++] = c;
}
I hope this helps if you find any problem. Please comment below. Don't forget to give a thumbs up if you liked it. :)
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