In the circuit shown, the capacitor is initially uncharged. At time t = 0, switch S is closed. If tau denotes the time constant, the approximate current through the 3Ω resistor when t = τ/10 is

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0.38A 0.50A 0.75A 1.0A 1.5A

Answer 1

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Answer #1

When the switch is closed, the capacitor charges. The chargingcurrent is given by

i = Ie^-t/τ

Where

I= V/R = 10/(3+6) = 10/9 = 1.11A

τ= RC = (6+3) (6μ) = 54μsec

At t=τ/10

i = Ie^-τ/10τ

i = 1.11 e jkgkjg

i = 1.1

i=1A

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Answer 2

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