Arrivals to a bank automated teller machine (ATM) are
distributed according to a Poisson distribution with a mean equal
to five per 10 minutes.
Determine the probability that in a given 10-minute segment, two
customers will arrive at the ATM.
a. 0.0842
b.0.1247
c.0.0028
d. 0.9942
what is the probability that fewer than two customers will arrive in a 30 minutes segment?
a. 0.0028
b. 0.0000
c. 0.0842
d. 0.9942
Formula for poisson distribution is (e^-u * u^x)/x!
Where e = 2.718, u is mean which is 5 and x is 2 as per question.
Substitute the values
e^ -5 = 0.006741
5^2 = 25
Probability= (0.006741*25)/2 = 0.0842
Similarly fewer than 2 means per 30 minutes means (2/3) which is 0 in 10 minutes. Hence value is 0.
Arrivals to a bank automated teller machine (ATM) are distributed according to a Poisson distribution with...
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