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A 400-turn circular coil (radius = 1.0 cm) is oriented with its plane perpendicular to a uniform...

A 400-turn circular coil (radius = 1.0cm) is oriented with its plane perpendicular to a uniform magneticfield which has a magnitude thatvaries sinusoidally with afrequency of 90 Hz. If the maximum value of the induced emf in thecoil is observed to be 4.2 V, what is the maximum value of themagnitudeof the varying magnetic field?



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Answer #1
Givenradius r= 1.0cm =1.0*10-2mfrequency f = 90Hzinduced emf ε = 4.2VNumber of turns N = 400------------------------------------------------------------------------magnetude of induced emf ε = NBAω sinθε= N B (πr2) ω sin θ=NB(πr2) (2πf) Sinθmaximum value of magnetic field B = ε /[Nπr2( 2πf)] ( SinceSin 90o = 1 )substittute the values for B
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Answer #2

Given Data, Number of tum in circular coil, N= 400 Radius of coil,r 1 cm Frequency of magnetic field, f 90 Hz Max value of induced emf, 4.2V Calculate value of angular velocity Here, ? is the angular velocity Substitute the values in the above equation a) 2TX90 565.487 rad/sec Consider the relation between magnetic flux and induced emf. ot - NAoB cos at The induced emf will be maximum when cos ot 1 sNAoB Here, A is area of circular coil in one tum Calculate the area of the coil A-Tr

Substitute the values in the above equation. A=TX12 -3.14 cm2 3.14x10 m Substitute the values in equation (1) 4.2 400 x3.14x1

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