Question

Problem 7:

A baseball batter hits a home run ball with a velocity of 132 ft/s at an angle of 26° above the horizontal. A fielder who has a reach of 7 ft above the ground is backed up against the bleacher wall, which is 386 ft from home plate. The ball was 3 ft above the ground when hit. How high above the fielder's glove does the ball pass?

Answer 1

Projectile nation's 14 dl Portal Equotion : of = ditut. whale di = 0, xf = 38687 = 117.653m. V= 132 (OS 26". = 40.2336 cos 26° It see (mis) MP-117-05) = 40.2336605 26(+) = 36.1044) 5€ 3.25 sec. vertical Equations- Ug = vitat If = Y; + vit that? V = v;*720194-Y;) where, I = 3ft = 6.914m yf = ? Sin - 1.17 2651763.mises. v;= 40-231 ( y = ? a = -9.891 +=? (i) vf = 17.63+ (-9.817. (in y = 0.114+ 17.63+++(-1-3)+ föry = 17.63+26.9.8) (94-0.914). From horizontal motion equation, t= 1.25 sec subtitute t = 3.25 in eq sep (in)

264 74 - 6-94+17.63 (325)+ { (-7-8)(3-25) = 6.914+57.2975 -57.75 If = 64615 m If = 6:46155 but the fielder can reach only 74 ( 2.134m) above the ground. : The Ball is (6.4 615 - 2:34) m above the glove. The ball 4.3275m 8 432.5 cm or 14ft 2.2 in above the glove