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A 30.6 kg mass is suspended by the cable assembly as shown in the figure below....

A 30.6 kg mass is suspended by the cable assembly as shown in the figure below. The cables have no mass of their own. The cable to the left (cable 1) of the mass makes an angle, 01=0.00* (degrees) with the horizontal, and the cable to the right (cable 2) makes an angle, 02=38.5*. If the mass is at rest, what is the tension in each of the cables T1 and T2? The acceleration due to gravity is 9.81 m/s2.

Options: a) 244 and 366 N b) 244 and 482 N c) 377 and 482 N d) 377 and 366 N

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Answer #1

>T2 cos θ

Taking the summation of forces in the vertical direction:

Tisin (38.5)-W

12 sin(38.5) 30.6 × 9.81

T, (30.6 × 9.81)// sin (38.5) 182N

Now Taking the summation of forces in the horizontal direction:

Ti -T2cos(38.5)

11-482cos(38.5) 377N

Hence T1 = 377 N and T_2 = 482 N

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