Question

​A block having a mass of m = 14 kg is suspended via two cables as shown in the figure. The angles shown in the figure are as follows:

A block having a mass of m = 14 kg is suspended via two cables as shown in the figure. The angles shown in the figure are as follows: α = 14° and β =37°. We will label the tension in Cable I as T1 and the tension in Cable 2 as T2.


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 Part (a) Please use the interactive area below to draw the Free Body Diagram for the block.

 Part (b) Write an expression for the sum of forces in the x direction in terms of T1, T2, m, g, α, and β. Use the specified coordinate system.

 Part (c) Write an expression for the sum of forces in the y direction in terms of T1, T2, m, g, α, and β.. Use the specified coordinate system.

 Part (d) Solve for the numeric value of T1, in newtons.

 Part (c) Solve for the numeric value of T2, in newtons.


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Answer #1

Part (a)

.

Part (B)

Consider all forces in x direction

ANSWER: -------------(1)

========================

Part (c)

Consider all forces in y direction

ANSWER: -------------(2)

============================

Part (d) and Part (e)

From (1)

------------(3)

============

From(2)

Put (3) in above equation

ANSWER:

======================

From(3)

ANSWER:

======================

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