A particle starts from x0 = 15 m at t0 = 0 and moves with the velocity graph shown in (Figure 1)

Question

Question

Part B

You may want to review (Pages 41 - 43) What is the object's position at t 2s?

Part C

What is the object's position at t 4s?

Answer 1

Answer #1

b)

Object's position at t=2 s is

X(t=2) =X_o+Area under the graph from t=0 to t=2 s

X(t=2) =15+ (1/2)*(-4)*(1-0)+(1/2)*4*(2-1)

X(t=2) =15 m

c)

at t=4 s

X(t=4) =X_o+Area under the graph from t=0 to t=4 s

X(t=4) =15+ (1/2)*(-4)*(1-0)+(1/2)*12*(4-1)

X(t=4) =31 m

Answer 2

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