Question

The figure below is the velocity-versus-time (not position-versus-time!) graph of a particle in simple harmonic motion. 

 (a) What is the amplitude of the oscillation?

 (b) What is the phase constant? 

 (c) What is the position at t=0s?

Answer 1

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PART (a):

From the graph, we have time period, T = 12 s

Hence, Angular frequency is given by:

We know that, Maximum velocity is given by:

Where, A is the amplitude of SHM.

Therefore, Amplitude of the oscillation is given by:

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PART (b):

We know that, velocity is given by:

At t = 0 s, V = -30 cm/s = -0.3 m/s

Substituting values:

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PART (c):

Position at t= 0 s is given by:

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