The uniform thin rod in the figure below has mass M = 4.00 kg and length L = 2.21 m and is free to rotate on a frictionless pin. At the instant the rod is released from rest in the horizontal position, find the magnitude of the rod's angular acceleration, the tangential acceleration of the rod's center of mass, and the tangential acceleration of the rod's free end.
(a)
the rod's angular acceleration (in rad/s2)
rad/s2
(b)
the tangential acceleration of the rod's center of mass (in m/s2)
m/s2
(c)
the tangential acceleration of the rod's free end (in m/s2)
m/s2
This problem is based on newton law used in rotational motion as explained below...
The uniform thin rod in the figure below has mass M = 4.00 kg and length...
The thin uniform rod in the figure has length 7.0 m and can pivot about a horizontal, frictionless pin through one end. It is released from rest at angle θ = 40° above the horizontal. Use the principle of conservation of energy to determine the angular speed of the rod as it passes through the horizontal position. Assume free-fall acceleration to be equal to 9.83 m/s2.
A uniform rod of length L (2.00 m) and mass M (5.00 Kg) is free to rotate on a frictionless pin passing through one end. The rod is released from rest in the horizontal position, (a) What is its angular speed when the rod reaches its lowest position? (b) What arc the linear speed of the center of mass and that of the lowest point on the rod when it is in the vertical position?
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