Figure below shows a insulating rod having a uniformly distributed charge Q, the rod has been bent in a 120 degree circular arc of radius r. We place coordinate axes such that the axis of symmetry of the rod lies along the x axis and the origin is at the center of curvature P of the rod. In terms of Q and r, (a) what is the electric field due to the rod at point P (b) What is the direction of the electric field?
Figure below shows a insulating rod having a uniformly distributed charge Q, the rod has been bent in a 120 degree circular arc of radius r.
In the figure a plastic rod having a uniformly distributed charge Q = 18.1 pC has been bent into a circular arc of radius 3.94 cm and central angle 120°. With V = 0 at infinity, what is the electric potential in volts at P, the center of curvature of the rod?
In the figure a plastic rod having a uniformly distributed charge Q = -27.0 pC has been bent into a circular arc of radius 1.73 cm and central angle 120 degrees. With V = 0 at infinity, what is the electric potential in volts at P, the center of curvature of the rod?
A thin insulating rod is bent into a semicircular arc of radius a, and a total electric charge Q is distributed uniformly along the rod. Calculate the potential at the center of curvature of the arc if the potential is assumed to be zero at infinity. (Use any variable or symbol stated above along with the following as necessary: ε0.)
A semi-circular, insulating rod has radius R and lies in the xy-plane. It carries a total charge Q. The center of curvature (i.e., the center of the circle of which this is a part) is at the origin, and the rod itself is in the first and second quadrants. Find the electric field vector produced by this charge distribution at the origin.
In the figure shown above, a plastic rod having a uniformly distributed charge -4.2 mu or micro C has been bent into a circular arc of radius 24 cm and central angle 101degrees (degrees). With V = 0 at infinity, what is the electric potential at P, the center of curvature of the rod?
Figure 22-47 a shows a nonconducting rod with a uniformly distributed charge +Q. The rod forms a 10/22 of circle with radius R and produces an electric field of magnitude Earc at its center of curvature P. If the arc is collapsed to a point at distance R from P (Figure 22-47b), by what factor is the magnitude of the electric field at P multiplied?
A plastic (non-conducting) rod is bent into a circular arc of radius 20.00 cm subtending an arc of 100 degree. One half of the rod has a uniformly distributed (positive) charge of +8.00 pC and the other half of the rod has a uniformly distributed (negative) charge of -8.00 pC; the two charges do not neutralize each other. Determine the magnitude and orientation of the electric field produced at the centre of curvature, C.
A charge of 17 nC is uniformly distributed along a straight rod of length 4.4 m that is bent into a circular arc with a radius of 2.1 m. What is the magnitude of the electric field at the center of curvature of the arc?
8. A charge of 20 nC is uniformly distributed along a straight rod of length 4.0m. If is then bent into a circular arc of radius 2.0 m. What is the magnitude of the electric field at the center of curvature of the arc?
A charge of 18 nC is uniformly distributed along a straight rod of length 11 m that is bent into a circular arc with a radius of 3.7 m. What is the magnitude of the electric field at the center of curvature of the arc?