Question

A semi-circular, insulating rod has radius R and lies in the xy-plane. It carries a total charge Q.


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A semi-circular, insulating rod has radius R and lies in the xy-plane. It carries a total charge Q. The center of curvature (i.e., the center of the circle of which this is a part) is at the origin, and the rod itself is in the first and second quadrants. Find the electric field vector produced by this charge distribution at the origin.

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Answer #1

Let us draw the diagram from the description of the problem

:

The electric field due to the infinitesimal element at the origin is

corresponding to this element there lies another element of the symmetrically opposite side of the y-axis. the electric field in the y-axis is exactly equal and opposite and hence is cancelled out, however, due to this symmetrically opposite element also, the electric field along the x-axis is same.

Hence the net electric field due to all such infinitesimal elements will be only along -ve x-direction.

Hence we only need to calculate the field along the negative x-direction

Here

Hence

[we will integrate over from 0 to ]

  

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