Question

Problem 1 A curved plastic rod of charge +Q forms a semi-circle of radius R in the x-y plane, as shown below on the left. The charge is distributed uniformly across the rod. dQ +0 +Q Now let's analytically determine the magnitude and direction of the electric field E at the center of the circle using polar coordinates and the charge element dQ shown in the image on the right. write down an expression for the electric field dE at the center of the circle due to this element d Q. Hints: A) Remember, dE is a vector, write using the 1, J notation. B) your answer should be written in terms of R, θ C) Use that dQA dl where now λ is the linear charge density λ:01 (total · charge/divided by total length) D) Use polar coordinates where dl-Rde Write down the integral you need to do to solve for Ex and Ey at the center of the semi-circle (be sure to specify the limits of integration) .What is the result of these two integrals? You may need to use .What is the magnitude of the total E field at the center? .Using a symmetry argument, what will be the E field at the center created by a negatively charged half ring in the bottom half

Answer 1