A sample of pond sediment was diluted by placing a 0.1 g into 9.9 ml of...
Homework Answers
The density of the sediment is about that of water = 1gm/ml
Therefore, when 0.1 gm of sediment was diluted into 9.9ml of diluent,
Dilution factor=0.1 gm x 1 gm/ml / 10 ml (Total volume of solution) = 0.01
CFU/gm = No of colonies / Dilution factor = 198 / 0.01 = 19800
CFU/gm = No of colonies / Dilution factor = 186 / 0.01 = 18600
If we take the average = (19800+18600) / 2 = 19200 CFU/gm
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