A small glass bead has been charged to + 40.0 nC . A small metal ball bearing 1.00 cm above the bead feels a 1.10×10−2 N downward electric force.What is the charge on the ball bearing?
As the metal ball bearing is experiencing a downward electric force, it implies the metal ball is negatively charged and hence it is attracted to the glass bead.
The magnitude of the electric force = kq1q2/r^2
q1 = 40 nC
r = 0.01 m
F = 1.10×10−2 N
k = Coulomb's constant = 9×10^9 N-m2/C2
q2 = F*r^2/kq1 = 1.10×10−2 N * 0.01*0.01/(9×10^9 N-m2/C2*40*10^-9 C) = 3.055*10^-9 C = 3.055 nC
Taking sign into consideration, q2 = -3.055 nC
A small glass bead has been charged to + 40.0 nC . A small metal ball...
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