The two forces F1 and F2 shown in figure 1 act on a 23.0kg object on a frictionless tabletop. Suppose that F1 = 12.0 N and F2 = 18.8 N.
Determine the magnitude of the net force on the object for the
diagram (a) in the figure.
Net Force on object will be
Fnet = F1 + F2
F1 = 12 N in -ve x-axis = -12 i
F2 = 18.8 N in -ve y-axis = -18.8 j
So,
Fnet = -12 i - 18.8 j
Now magnitude of net force will be
|Fnet| = sqrt ((-12)^2 + (-18.8)^2)
|Fnet| = 22.3 N
Direction of Net force will be
direction = arctan ((-18.8)/(-12)) = 57.4 deg below -ve x-axis
direction = 180 + 57.4
Direction = 237.4 deg Counterclockwise from +ve x-axis
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The two forces F1 and F2 shown in figure 1 act on a 23.0kg object on a frictionless tabletop. Suppose that F1 = 12.0 N and F2 = 18.8 N.
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