Question

As shown in the figure, a force of magnitude 7.50 N pushes three boxes with masses m₁ = 1.30 kg, m₂ = 3.80 kg, and m₃ = 5.30 kg.

(Figure shows three boxes, 1 2 and 3 with a force pushing them)

(a) Find the magnitude of the contact force between boxes 1 and 2.


(b) Find the magnitude of the contact force between boxes 2 and 3.

Answer 1

As shown in the figure, a force of magnitude 7.50 N pushes three boxes with masses m₁ = 1.30 kg, m₂ = 3.80 kg, and m₃ = 5.30 kg.

(Figure shows three boxes, 1 2 and 3 with a force pushing them)

(a) Find the magnitude of the contact force between boxes 1 and 2.

(b) Find the magnitude of the contact force between boxes 2 and 3.

The total mass of the boxes is 10.40 kg, and the force being supplied is 7.50 N. If we neglect friction, the acceleration of the total mass is:

a = F/m = (7.50 N)/(10.40 kg) = 0.798 0.721153846 m / s² So each box is accelerating at 0.721 m/s

Answer 2

Fnet = (m1+m2+m3)*a

a = Fnet/(m1+m2+m3)

= 7.5/(1.3+3.8+5.3)

= 0.72 m/s^2

a) F12 = a*(m2+m3)

= 0.72*(3.8+5.3)

= 6.55 N

b) F23 = a*m3

= 0.72*5.3

= 3.82 N

Answer 3

The total mass of the boxes is 10.40 kg, and the force being supplied is 7.50 N. If we neglect friction, the acceleration of the total mass is:

a = F/m = (7.50 N)/(10.40 kg) = 0.721 m/s