Calculate the equilibrium electrode potential for Fe3+/Fe2+ redox system, if the initial concentration of Fe2+ is...
Calculate the equilibrium electrode potential for Fe3+/Fe2+ redox system, if the initial concentration of Fe2+ is of 0.1 mol/L and one third of Fe2+ is oxidized to Fe3+ at pH 1.
(eo(Fe3+/Fe2+) = 0.77 V)
Homework Answers
The balanced reaction will be
The concentration of Fe(2+) will be 0.1 * 2/3 and concentration of Fe(3+) in the reaction which is 0.1 * 1/3
Hence the equilibrium electrode potential will be equal to 0.752 V
Note - Post any doubts/queries in comments section.
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Calculate the equilibrium electrode potential for Fe3+/Fe2+
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Calculate the potential of the indicator electrode when 40% of Fe2+ has been titrated with Ce(IV). Fe2+ +Ce4+ <--> Fe3+ + Ce3+ (Fe3+/Fe2+): E=0.771 V (Ce4+/Ce3+): E=1.44 V
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7.53 Given the following electrode potentials at 25°C, Fe3+ +e- = Fe2+ E' = 0.771 V Fe2+ + e = Fe(s) E = -0.440 V calculate the electrode potential for [Fe3+ + e = {Fe E; = ? for
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Please show all of your work!
TP1 + 2Pe2t TV +2Fe3t B" Tqi/TT+ = 1.25 V; E0Feat n®/Tlt-1.25 V, E0Fe2+/Fe2+ = 0.771V
2. What is the potential that is developed in platinum electrode ys ESC after being submerged in a solution of Fe3+ 0.018M and Fe2+ 0.0055M? Eo Fe3+/Fe2+ = +0.77 V. Eesc = +0.244 V
Need help solving this question
Calculate AG° /mol of permanganate ions for a REDOX reaction in which permanganate is reduced to Mn2+ (E° = 1.51 V) while Fe2+ is oxidized to Fe3+ (EO = -0.77 V), under acidic conditions. a. -71.4 kj b.-286 kJ C. -357 kJ d.-428 kJ
+ Given the following electrode potentials at 25°C Fe3+ e-- Fe2+ E° = 0.571 V 2e Fe(s) E° = -0.440 V Calculate the electrode potential for Fe3+ + 3 e- Fe(s) Fe2+ + Select one: a. -0.132 b. -0.036 c. 0.081 d.-0.211 e. 0.103
7.53 Given the following electrode potentials at 25°C, Fe3+ +e- = Fe2+ E' = 0.771 V Fe2+ + e = Fe(s) E = -0.440 V calculate the electrode potential for [Fe3+ + e = {Fe E; = ? for
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Please show all of your work!
TP1 + 2Pe2t TV +2Fe3t B" Tqi/TT+ = 1.25 V; E0Feat n®/Tlt-1.25 V, E0Fe2+/Fe2+ = 0.771V
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