Using the following standard reduction potentials: Fe3+ (aq) + e. → Fe2+ (aq) Eo = +0.77...
Using the following standard reduction potentials Fe3+(aq) + e- → Fe2+(aq) E° = +0.77 V Pb2+(aq) + 2 e- → Pb(s) E° = -0.13 V calculate the standard cell potential for the galvanic cell reaction given below, and determine whether or not this reaction is spontaneous under standard conditions. Pb2+(aq) + 2 Fe2+(aq) → 2 Fe3+(aq) + Pb(s) Group of answer choices E° = -0.90 V, spontaneous E° = -0.90 V, nonspontaneous E° = +0.90 V, nonspontaneous E° = +0.90...
Using the standard reduction potentials given below, choose the reaction than can only be achieved through electrolysis. Cu2+(aq) + 2e → Cu(s) E° = 0.34 V Pb2+(aq) + 2e + Pb(s) E° = -0.13 V Fe2+(aq) + 2e Fe(s) E° = -0.44 V Zn2+(aq) + 2e + Zn(s) E° = -0.77 V Zn2+(aq) + Pb(s) → Zn(s) + Pb2+(aq) o Fe2+(aq) + Zn(s) → Fe(s) + Zn2+(aq) Pb2+(aq) + Fe(s) → Pb(s) + Fe2+(aq) Cu2+(aq) + Fe(s) → Cu(s) +...
Use the following standard cell potentials to answer the questions below. Fe3+(aq) + e− ⇌ Fe2+(aq) E° = 0.771 V Ag3+(aq) + e− ⇌ Ag2+(aq) E° = 1.800 V 1. What is ΔG° (in kJ/mol) for this reaction? Report answer to three significant figures in scientific notation (i.e., 1.23e2 kJ/mol) 2. This reaction is (spontaneous/not spontaneous)
Consider the following cell: Pt(s) | Fe3+ (aq). Fe2(aq) | CIF (aq) C12(e) Pt(s) If the standard reduction potentials of the Fe3+/Fe2+ and Cl2/Cl" couples are +0.77 and +1.36 V, respectively, calculate the value of Efor the given cell. +1.00 V O +1.77 v +0.59 V +2.13 V +0.95 V
Two standard reduction potentials are given below. Pb2+(aq) + 2 e− → Pb(s) E⁰red = −0.126 V Cl2(g) + 2 e− → 2 Cl−(aq) E⁰red = +1.358 V (a) Which is a stronger reducing agent, Pb(s) or Cl−(aq)? Pb(s) ; or Cl−(aq) (b) Which is the most difficult to oxidize, Pb(s) or Cl−(aq)? Pb(s); or Cl−(aq) (c) Is Pb(s) able to reduce Cl2(g) in a spontaneous reaction? is able; or is not able (d) Is Cl−(aq) able to reduce Pb2+(aq)...
Separate galvanic cells are made from the following half-cells: cell 1: H+(aq)/H2(g) and Pb2+(aq)/Pb(s) cell 2: Fe2+(aq)/Fe(s) and Zn2+(aq)/Zn(s) Which of the following is correct for the working cells? Standard reduction potentials, 298 K, Aqueous Solution (pH = 0): Cl2(g) + 2e --> 2C1-(aq); E° = +1.36 V Fe3+(aq) + e --> Fe2+(aq); E° = +0.77 V Cu2+(aq) + 2e --> Cu(s); E° = +0.34 V 2H+(aq) + 2e --> H2(g); E° = 0.00 V Pb2+(aq) + 2e --> Pb(s);...
The following standard reduction potentials have been determined for the aqueous chemistry of iron: Fe3 (a)e>Fe2-(aq 0.770 V Fe2 (aq) 2e>Fe(s E°-0.409 v Calculate the equilibrium constant (K) for the disproportionation of Fe2(aq) at 25 °C. Submit Answer 5 question attempts remaining
6. Consider the following galvanic cell and standard reduction potentials: Ag Pb E° = 0.80 V salt bridge Ag+ (aq) + e → Ag(s) Pb2+(aq) + 2e → Pb(s) E° = -0.13 V 1 M Ag+ 1 M Pb2+ Which one of the following statements is TRUE? a) The cell on the left containing Ag+(aq) is the anode. b) The initial reading on the voltmeter would be 0.67 V. c) Oxidation occurs in the cell on the right containing Pb²+(aq)....
Design a voltaic cell with the following two reduction half-reactions: Ag+(aq) + e− ⟶ Ag(s) Eo = 0.80 V Pb2+(aq) + 2 e− ⟶ Pb(s) Eo = −0.13 V Calculate Eocell and the equilibrium constant K for the voltaic cell at 298 K. Click here for a copy of Final Exam cover sheet.
1. Consider the following standard reduction potentials, Pb 2 +(aq) + 2 e- → Pb(s) E° = -0.13 V I2(s) + 2 e- → 2 I-(aq) E° = +0.54 V Under standard conditions, Consider the following standard reduction potentials, Pb 2 +(aq) + 2 e- → Pb(s) E° = -0.13 V I2(s) + 2 e- → 2 I-(aq) E° = +0.54 V Under standard conditions, I2(s) is a stronger oxidizing agent than Pb 2+(aq) and Pb(s) is a stronger reducing...