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6. Consider the following galvanic cell and standard reduction potentials: Ag Pb E° = 0.80 V salt bridge Ag+ (aq) + e →...
Hi. can some one please explain me the solution for this question. the correct answer is...
Hi. can some one please explain me the solution for
this question. the correct answer is C. thanks.
8. Consider the following galvanic cell and standard reduction potentials: Ag (aq) + e → Ag(s) E=0.80 V Pb²+ (aq) + 2e → Pb(s) E = -0.13 V IMA Which one of the following statements is TRUE? a) The cell on the left containing Ag (aq) is the anode. b) The initial reading on the voltmeter would be 0.67 V. c) Oxidation...
Standard reduction potentials for the Zn2+/Zn and Pb2+/Pb couples are -0.76 and - 0.13 V, respectively....
Standard reduction potentials for the Zn2+/Zn and Pb2+/Pb couples are -0.76 and - 0.13 V, respectively. The galvanic cell below uses the half-cells Pb2+ Pb and Zn2+|Zn, and a salt bridge containing KCl(aq). The voltmeter gives a positive voltage reading. voltmeter salt bridge CD- <-CD-RB B The electrode B could be inert platinum metal or lead metal. O True O False
Question 5 (1 point) Standard reduction potentials for the Zn2+/Zn and Pb2+/Pb couples are -0.76 and...
Question 5 (1 point) Standard reduction potentials for the Zn2+/Zn and Pb2+/Pb couples are -0.76 and - 0.13 V, respectively. The galvanic cell below uses the half-cells Pb2 Pb and Zn2+Zn, and a salt bridge containing KCl(aq). The voltmeter gives a positive voltage reading. voltater salt bridge CD- The identities of A and C, respectively, are Zn and K OPb and K Zn and CH O Pb and CI Question 6 (1 point) Saved In a working electrochemical cell, the...
Question 7 (1 point) Standard reduction potentials for the Zn2+/Zn and Pb2+/Pb couples are -0.76 and...
Question 7 (1 point) Standard reduction potentials for the Zn2+/Zn and Pb2+/Pb couples are -0.76 and - 0.13 V, respectively. The galvanic cell below uses the half-cells Pb2+[Pb and Zn2+|Zn, and a salt bridge containing KCl(aq). The voltmeter gives a positive voltage reading. voltmeter salt bridge CD-> The identities of B and D, respectively, are O Pb and Cl- Ozn and Cl- O Pb and K+ O Zn and K+
Half-cell Potentials: Half Reaction: E value +0.80 V Agt + e → Ag Fe3+ + €...
Half-cell Potentials: Half Reaction: E value +0.80 V Agt + e → Ag Fe3+ + € → Fe2+ +0.77 v +0.34 V -0.13 V Cu2+ +2e → Cu Pb2+ + 2e - → Ib Ni2+ + 2e → Ni Cd2+ +2e → Cd -0.25 V -0.40 V Fe2+ + 2e → Fe -0.44 V Zn2+ + 2e → Zn -0.76 V Al3+ +3e → AI - 1.66 V Consider an electrochemical cell constructed from the following half cells, linked by...
Consider a voltaic cell based on the half-cells: Ag+ (aq) + e - Ag(s) E* =...
Consider a voltaic cell based on the half-cells: Ag+ (aq) + e - Ag(s) E* = +0.80 V Pb2+(aq) + 2 e-Pb(s) E* = -0.13 V Identify the anode and give the cell voltage under standard conditions: = 0.67 V Ag: E cell B. Pb: E cell = 0.67 V OC. Pb: E cell = 0.93 V D. Pb: E cell = -0.67 V E. Ag: E cell = 0.93 V
HIU Blud cell potential of a galvanic cell based on the following reduction half- reactions at...
HIU Blud cell potential of a galvanic cell based on the following reduction half- reactions at 25 °C Cd + 2e → Cd Eº - -0.403 V Pb2+2e → Pb Eº - -0.126 V where (Cd-) - 0.040 M and (Pb) - 0.400M (13.) A zinc electrode is submerged in an acidic 0.40 M Zn?' solution which is connected by a salt bridge to a 1.50 M Ag' solution containing a silver electrode. Determine the initial voltage of the cell...
19 20 Question 16 Half-cell Potentials: Half Reaction: E' value + 0.80 V +0.77 V Agte...
19 20 Question 16 Half-cell Potentials: Half Reaction: E' value + 0.80 V +0.77 V Agte → AS Fe3+ + + Fe2+ Cu2+ 2e → Cu Pb2+ + 2e → Pb +0.34 V -0.13 V Ni2+ + 2e → NI -0.25 V - 0.40 V Cd2+ +2e → ca Fe2+ + 2e → Fe Zn2+ + 2e → Zn -0.44 V - 0.76 V A13+ +3 → AI - 1.66 V Consider an electrochemical cell constructed from the following half...
Two half-reactions are shown with their standard cell potentials. If a galvanic cell is constructed using...
Two half-reactions are shown with their standard cell potentials. If a galvanic cell is constructed using them, which electrode would be the anode, and what would the cell potential be? Fe2+ (aq) + 2e → Fe(s); E=-0.44 V Ag+(aq) + 1e → Ag(s); E=0.80 V O a. Iron, 1.24 V O b. Silver, 0.36 V O c. Iron, 0.36 V O d. Iron, -0.36 V O e. Silver, -0.36 V
Pb^2+ +2e- __> Pb e=-0.13V Ag+ +1e-__> Ag e=+0.80V Pb(s)| Pb2+ (1M) || Ag+ (1M) |...
Pb^2+ +2e- __> Pb e=-0.13V Ag+ +1e-__> Ag e=+0.80V Pb(s)| Pb2+ (1M) || Ag+ (1M) | Ag(s) Determine which of the following statements about the cell shown are True or False. The silver half-cell is the cathode. True False The mass of the silver electrode is decreasing. True False Anions move to the silver half-cell. True False Electrons are spontaneously produced in the lead half-cell. True False The cell, as represented by the line notation, is a voltaic cell. True False The standard cell potential,...
Hi. can some one please explain me the solution for
this question. the correct answer is C. thanks.
8. Consider the following galvanic cell and standard reduction potentials: Ag (aq) + e → Ag(s) E=0.80 V Pb²+ (aq) + 2e → Pb(s) E = -0.13 V IMA Which one of the following statements is TRUE? a) The cell on the left containing Ag (aq) is the anode. b) The initial reading on the voltmeter would be 0.67 V. c) Oxidation...
Standard reduction potentials for the Zn2+/Zn and Pb2+/Pb couples are -0.76 and - 0.13 V, respectively. The galvanic cell below uses the half-cells Pb2+ Pb and Zn2+|Zn, and a salt bridge containing KCl(aq). The voltmeter gives a positive voltage reading. voltmeter salt bridge CD- <-CD-RB B The electrode B could be inert platinum metal or lead metal. O True O False
Question 5 (1 point) Standard reduction potentials for the Zn2+/Zn and Pb2+/Pb couples are -0.76 and - 0.13 V, respectively. The galvanic cell below uses the half-cells Pb2 Pb and Zn2+Zn, and a salt bridge containing KCl(aq). The voltmeter gives a positive voltage reading. voltater salt bridge CD- The identities of A and C, respectively, are Zn and K OPb and K Zn and CH O Pb and CI Question 6 (1 point) Saved In a working electrochemical cell, the...
Question 7 (1 point) Standard reduction potentials for the Zn2+/Zn and Pb2+/Pb couples are -0.76 and - 0.13 V, respectively. The galvanic cell below uses the half-cells Pb2+[Pb and Zn2+|Zn, and a salt bridge containing KCl(aq). The voltmeter gives a positive voltage reading. voltmeter salt bridge CD-> The identities of B and D, respectively, are O Pb and Cl- Ozn and Cl- O Pb and K+ O Zn and K+
Half-cell Potentials: Half Reaction: E value +0.80 V Agt + e → Ag Fe3+ + € → Fe2+ +0.77 v +0.34 V -0.13 V Cu2+ +2e → Cu Pb2+ + 2e - → Ib Ni2+ + 2e → Ni Cd2+ +2e → Cd -0.25 V -0.40 V Fe2+ + 2e → Fe -0.44 V Zn2+ + 2e → Zn -0.76 V Al3+ +3e → AI - 1.66 V Consider an electrochemical cell constructed from the following half cells, linked by...
Consider a voltaic cell based on the half-cells: Ag+ (aq) + e - Ag(s) E* = +0.80 V Pb2+(aq) + 2 e-Pb(s) E* = -0.13 V Identify the anode and give the cell voltage under standard conditions: = 0.67 V Ag: E cell B. Pb: E cell = 0.67 V OC. Pb: E cell = 0.93 V D. Pb: E cell = -0.67 V E. Ag: E cell = 0.93 V
HIU Blud cell potential of a galvanic cell based on the following reduction half- reactions at 25 °C Cd + 2e → Cd Eº - -0.403 V Pb2+2e → Pb Eº - -0.126 V where (Cd-) - 0.040 M and (Pb) - 0.400M (13.) A zinc electrode is submerged in an acidic 0.40 M Zn?' solution which is connected by a salt bridge to a 1.50 M Ag' solution containing a silver electrode. Determine the initial voltage of the cell...
19 20 Question 16 Half-cell Potentials: Half Reaction: E' value + 0.80 V +0.77 V Agte → AS Fe3+ + + Fe2+ Cu2+ 2e → Cu Pb2+ + 2e → Pb +0.34 V -0.13 V Ni2+ + 2e → NI -0.25 V - 0.40 V Cd2+ +2e → ca Fe2+ + 2e → Fe Zn2+ + 2e → Zn -0.44 V - 0.76 V A13+ +3 → AI - 1.66 V Consider an electrochemical cell constructed from the following half...
Two half-reactions are shown with their standard cell potentials. If a galvanic cell is constructed using them, which electrode would be the anode, and what would the cell potential be? Fe2+ (aq) + 2e → Fe(s); E=-0.44 V Ag+(aq) + 1e → Ag(s); E=0.80 V O a. Iron, 1.24 V O b. Silver, 0.36 V O c. Iron, 0.36 V O d. Iron, -0.36 V O e. Silver, -0.36 V
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