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Question 5 (1 point) Standard reduction potentials for the Zn2+/Zn and Pb2+/Pb couples are -0.76 and - 0.13 V, respectively.
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Answer #1

5. As we know

in electrochemical cell,

Left is anode, anode is always - ve.

Right is cathode, cathode is always +ve.

reduction potential of Zn2+/Zn =-0.76V

reduction potential of Pb2+/Pb =0.13V

Thus reduction potential of Zn2+/Zn is less as compared to Pb2+/Pb. hence Zn electrode can be used to reduce Pb2+ to Pb. Also reduction (Pb2+to Pb) takes place at cathode. Then oxidation of Zn takes place at anode which is - ve.

So left side is Zn side. So the electrode A os Zn electrode.

Also - ve ions of salt bridge come towards anode.

So Cl- come towards anode.

Thus

A = Zn

C = Cl-

thus option c is correct.

basesd on above explanation. other options are incorrect.

6. the statement is false.

Because the flow of electron is from anode to cathode or from - ve electrode to +ve electrode.

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