Hi. can some one please explain me the solution for
this question. the correct answer is C. thanks.
Hi. can some one please explain me the solution for this question. the correct answer is...
6. Consider the following galvanic cell and standard reduction potentials: Ag Pb E° = 0.80 V salt bridge Ag+ (aq) + e → Ag(s) Pb2+(aq) + 2e → Pb(s) E° = -0.13 V 1 M Ag+ 1 M Pb2+ Which one of the following statements is TRUE? a) The cell on the left containing Ag+(aq) is the anode. b) The initial reading on the voltmeter would be 0.67 V. c) Oxidation occurs in the cell on the right containing Pb²+(aq)....
Hi. can some one please explain me the solution for
this question. the correct answer is B. thanks.
8. Consider the following concentration cell. Ag (aq) + e → Ag(s) E = 0.80 V 0.1 M Ag Which one of the following statements is TRUE? a) The electrode on the left containing 1 M Ag (aq) is the anode. b) Equilibrium occurs when the [Ag (aq) in both cells is equal. c) The initial reading on the voltmeter would be...
Standard reduction potentials for the Zn2+/Zn and Pb2+/Pb couples are -0.76 and - 0.13 V, respectively. The galvanic cell below uses the half-cells Pb2+ Pb and Zn2+|Zn, and a salt bridge containing KCl(aq). The voltmeter gives a positive voltage reading. voltmeter salt bridge CD- <-CD-RB B The electrode B could be inert platinum metal or lead metal. O True O False
Question 5 (1 point) Standard reduction potentials for the Zn2+/Zn and Pb2+/Pb couples are -0.76 and - 0.13 V, respectively. The galvanic cell below uses the half-cells Pb2 Pb and Zn2+Zn, and a salt bridge containing KCl(aq). The voltmeter gives a positive voltage reading. voltater salt bridge CD- The identities of A and C, respectively, are Zn and K OPb and K Zn and CH O Pb and CI Question 6 (1 point) Saved In a working electrochemical cell, the...
could someone please answer and explain the questions please!!
#’s 7,8,9,13,14,17,18,19,20
please and thank you
What is the oxidation number for the underlined manganese (A)1 (B)2 (C)4(D)(E)7 When balancing the below half-reaction in 8. Which of the following is true concerning a 1. vanic cc A) Oxidation occurs at the cathode and is (B) Oxidation occurs at the anode and is where anions move towards 2. acidic sol electrons are added to ution, where anions move towards side of.the.cquation. where...
Question 7 (1 point) Standard reduction potentials for the Zn2+/Zn and Pb2+/Pb couples are -0.76 and - 0.13 V, respectively. The galvanic cell below uses the half-cells Pb2+[Pb and Zn2+|Zn, and a salt bridge containing KCl(aq). The voltmeter gives a positive voltage reading. voltmeter salt bridge CD-> The identities of B and D, respectively, are O Pb and Cl- Ozn and Cl- O Pb and K+ O Zn and K+
Instead of using zinc, a student accidentally used a 1 M solution of silver (Ag). Based on the information in the table below, what would be the theoretical cell voltage, Eocell, when it is used in a galvanic cell with copper? Electrode Eo Ag+ + e- à Ag +0.80 V Cu2+ + 2e- à Cu +0.34 V Pb2+ + 2e- à Pb -0.13 V Zn2+ + 2e- à Zn -0.76 V Al3+ + 3e- à Al -1.66 V
HIU Blud cell potential of a galvanic cell based on the following reduction half- reactions at 25 °C Cd + 2e → Cd Eº - -0.403 V Pb2+2e → Pb Eº - -0.126 V where (Cd-) - 0.040 M and (Pb) - 0.400M (13.) A zinc electrode is submerged in an acidic 0.40 M Zn?' solution which is connected by a salt bridge to a 1.50 M Ag' solution containing a silver electrode. Determine the initial voltage of the cell...
19 20 Question 16 Half-cell Potentials: Half Reaction: E' value + 0.80 V +0.77 V Agte → AS Fe3+ + + Fe2+ Cu2+ 2e → Cu Pb2+ + 2e → Pb +0.34 V -0.13 V Ni2+ + 2e → NI -0.25 V - 0.40 V Cd2+ +2e → ca Fe2+ + 2e → Fe Zn2+ + 2e → Zn -0.44 V - 0.76 V A13+ +3 → AI - 1.66 V Consider an electrochemical cell constructed from the following half...
Consider a voltaic cell based on the half-cells: Ag+ (aq) + e - Ag(s) E* = +0.80 V Pb2+(aq) + 2 e-Pb(s) E* = -0.13 V Identify the anode and give the cell voltage under standard conditions: = 0.67 V Ag: E cell B. Pb: E cell = 0.67 V OC. Pb: E cell = 0.93 V D. Pb: E cell = -0.67 V E. Ag: E cell = 0.93 V