The only force acting on a 2.0-kg object moving along the x axis is shown. If the velocity Vx is +2.0 m/s at t = 0, what is the velocity at t = 4.0 s?
+6.0 m/s
+2.0 m/s
+7.0 m/s
+5.0 m/s
+4.0 m/s
in order to find the velocity at t = 4s we have to use the momentum impulse theorem.
F∆t = ∆p = m(v_i-v_f)
The only force acting on a 2.0-kg object moving along the x axis is shown. If...
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