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A uniform disk with mass 38.8 kg and radius 0.200 m is pivoted at its center...

A uniform disk with mass 38.8 kg and radius 0.200 m is pivoted at its center about a horizontal, frictionless axle that is stationary. The disk is initially at rest, and then a constant force 25.0 N is applied tangent to the rim of the disk.

a)What is the magnitude v of the tangential velocity of a point on the rim of the disk after the disk has turned through 0.170 revolution?

b)What is the magnitude a of the resultant acceleration of a point on the rim of the disk after the disk has turned through 0.170 revolution?

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Answer #1

The torque, (25) (38.8)(0.2) 6.44 rad s Use kinematic equation of motion o-0 2(6.44) (0.170) (27) 3.70 rad/s Therefore, the r

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