A uniform solid disk of mass m = 3.08 kg and radius r = 0.200 m...
A uniform solid disk of mass m = 3.08 kg and radius r = 0.200 m rotates about a fixed axis perpendicular to its face with angular frequency 6.09 rad/s.
(a) Calculate the magnitude of the angular momentum of the disk
when the axis of rotation passes through its center of mass.
kg · m2/s
(b) What is the magnitude of the angular momentum when the axis of
rotation passes through a point midway between the center and the
rim?
kg · m2/s
Homework Answers
angular momentum
L = Iw = 0.5 m r^2 w
L = 0.5* 3.08* 0.2^2* 6.09
L = 0.3751 kgm^2/s
=========
b)
new moment of ibertia
I' = I + m (r/2)^2
I' = 0.5* m r^2 + 0.25* m r^2
new angular momentum
L' = I' w = 0.75* 3.08* 0.2^2* 6.09
L' = 0.5627 kgm^2/s
=======
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