A uniform solid sphere of radius r=0.490 m and mass m=14.5 kg turns clockwise about a vertical axis through its center (when viewed from above), at an angular speed of 3.20 rad / s. What is its vector angular momentum about this axis?
(Enter the magnitude in kg · m² / s.)
Solution) R = 0.490 m
m = 14.5 kg
w = 3.20 rad/s
Angular momentum , L = ?
L = (I)(w)
I = (2/5)(m)(R^2)
I is moment of inertia of solid sphere
L = (2/5)(14.5)(0.490^2)(3.20)
L = 4.45 kgm^2/s
Direction is downwards
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