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6) Two point charges q1 = 4.0 μC and q2 = -8.0 μC are placed along...

6) Two point charges q1 = 4.0 μC and q2 = -8.0 μC are placed along the x-axis at x1 = 0 m and x2 =0.20 m, respectively. What is the electric potential energy of this system of charges?

7) Gauss's law can be applied using any surface. True/ false?

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Answer #1

6.)

As we know that electric potential energy of a system = K*q1*q2/r

Where 'r' is the seperation between them

So electric potential energy of given system = 9*10^9*4*10^-6*-8*10^-6/(0.20 - 0) = 1.44 J

7.)

Gauss law states that

The area integral of the electric field over any closed surface is equal to the net charge enclosed in the surface divided by the permittivity of space.

False because gauss law can be apply using those surfaces Whose area can be identified

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